2x^2-80x-450=0

Solution for 2x^2-80x-450=0 equation:

2x^2-80x-450=0

a = 2; b = -80; c = -450;
Δ = b2-4ac
Δ = -802-4·2·(-450)
Δ = 10000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{10000}=100$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-80)-100}{2*2}=\frac{-20}{4}
=-5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-80)+100}{2*2}=\frac{180}{4}
=45
$